[802.19] Question about path loss model

["Shellhammer, Steve" <sshellha@xxxxxxxxxxxx>]

Paul,

 

            I have a question about the path loss model you used in presentation 802.16h-07/38r1 on slide 11.

 

            The slide says the model is,

 

Propagation model

– d1=1m, d1=500m, d2=1000m, d3=4000m

– n1=2, n2=2.5, n3=3.5, n4=4

 

            I am a bit unclear on this.  There are four breakpoints and four exponents.  Typically, there are N breakpoints and N+1 exponents.  One interpretation is that the free space exponent of 2 is used between 1 and 500 meters.  Another interpretation is that free space is up to 1 meter and the exponent of 2.5 is used between 1 and 500 meters.

 

            Can you clarify your path loss model?

 

            I think it would be useful to have a common path loss model for everyone to use.

 

Thanks,

Steve