[STDS-802-16] FCH duplication in 1024-point FFT mode
Hello all,
In page 502 of [802.16-2004], the paragraph before 8.4.4.4, it said "Before being mapped to the FCH, the 24-bit
DL frame Prefix shall be duplicated to form a 48-bit block, ....". But how does it duplicate exactly?
For example, if the 24 bits content in OFDMA downlink frame prefix format is: b0, b1, b2, ...., b23,
the duplicated 48 bits are:
Case I: b0, b0, b1, b1, ...., b22, b22, b23, b23 or
Case II: b0, b1, ..., b22, b23, b0, b1, ..., b22, b23?
Any comments are appreciated.
Best regards,
Lepidus.
************* Email Confidentiality Notice ********************
The information contained in this e-mail message (including any attachments) may be confidential, proprietary, privileged, or otherwise exempt from disclosure under applicable laws. It is intended to be conveyed only to the designated recipient(s). Any use, dissemination, distribution, printing, retaining or copying of this e-mail (including its attachments) by unintended recipient(s) is strictly prohibited and may be unlawful. If you are not an intended recipient of this e-mail, or believe that you have received this e-mail in error, please notify the sender immediately (by replying to this e-mail), delete any and all copies of this e-mail (including any attachments) from your system, and do not disclose the content of this e-mail to any other person. Thank you!