Re: finally, the right SNR table
- TO: kardontchik.jaime@xxxxxxxxxxx
- Subject: Re: finally, the right SNR table
- From: BRIAN_LEMOFF@xxxxxxxxxxxxxxxxxxxxxxxxxx
- Date: Fri, 11 Jun 1999 08:28:24 -0700
- CC: stds-802-3-hssg@xxxxxxxx
- In-Reply-To: <37605E28.D2D385A7@xxxxxxxxxxxxxxxxxxx>
- Sender: owner-stds-802-3-hssg@xxxxxxxxxxxxxxxxxx
Jaime,
You give the impression below that 8b/10b + 4-WDM will not support
installed fiber! In fact, at 3.125 Gbaud, one can support ~300 meters of
standard 62.5 micron fiber. Of course, at 1.25-Gigasymbols/s, a much
longer distance can be supported.
-Brian Lemoff
HP Lsbs
______________________________ Reply Separator _________________________________
Subject: finally, the right SNR table
Author: Non-HP-kardontchik.jaime (kardontchik.jaime@xxxxxxxxxxx) at
HP-PaloAlto,mimegw2
Date: 6/10/99 5:54 PM
Hello 10G'ers,
And finally, the really correct complete SNR table that
should replace the one I presented in Idaho:
The Complete SNR Table
Architecture vs Optical SNR
1) 1000BASE-X - 1 dB
2) 8b/10b + 4-WDM - 5 dB
3) 10G-BASE-T- EVEN coding - 5.5 dB
4) 10G-BASE-T- Trellis coding - 4 dB
The main differences between the two 10 Gbps
solutions appear to be:
a) speed of the electronics and active optics
(1.25 GHz vs 3.125 GHz) (technology, cost)
b) optical fiber (installed fiber vs higher bandwidth
fiber to allow a reasonable timing budget margin for
the 0.32 nsec bit period solution). Waveshaping is
still an additional option in 10G-BASE-T to reduce
dispersion in the optical fiber and increase the link
length.
The full explanation for the last change (line # 2 in
the Table) follows below. I sent it for double-checking
to the same HP researcher and it looks correct to
him too:
" ... it occurred to me that I might be penalyzing twice
the 8b/10b + 4-WDM approach.
In my presentation, I wrote that this approach incurres
in a signal penalty due to the smaller bit period of 0.32
nsec (compared to the 1000BASE-X reference of 0.8 nsec).
This signal penalty (or difference in bit energies) is 4 dB.
10 * log (1 * 0.32) = - 5 dB
(compared to the 1000BASE-X reference of
10 * log(1 * 0.8) = - 1 dB).
Then, when I calculted the thermal noise of the
8b/10b + 4-WDM approach I said that we get here
another 4 dB penalty in noise because the bandwidth
is 3.125 GHz, instead of 1.25 GHz:
10 *log(3.125/1.25) = 4 dB
Therefore, I concluded, the total penalty of 8b/10b + 4-WDM
is 8 dB compared to the reference 1000BASE-X.
Shouldn't I have calculated the optical SNR of
8b/10b + 4-WDM compared to the 1000BASE-X as
follows ? :
Signal Power = the same as in 1000BASE-X = - 1 dB
(the power levels of 1000BASE-X and 8b/10b+4-WDM
are the same, only the bit energies are different).
Noise Power = (4kT/R) * B = (4kT/R) * 3.125 =
= Noise power of 1000BASE-X + 10*log(3.125/1.25)
= Noise power of 1000BASE-X + 4 dB
Hence, the optical SNR penalty of 8b/10b + 4-WDM compared
with the reference of 1000BASE-X should be only 4 dB.
Therefore, in the optical SNR table, at the end of the presentation,
the first two entries should be:
1) 1000BASE-X - 1 dB
2) 8b/10b + 4-WDM - 5 dB
(and not -1 dB and - 9 dB, respectively, as I wrote)"
Jaime
Jaime E. Kardontchik
Micro Linear
San Jose, CA 95131
email: kardontchik.jaime@xxxxxxxxxxx