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Hi all, I just pulled up my G.652 fiber dispersion Excel sheet to calculate the worst case dispersion numbers for the 8 CWDM channels mentioned by Scott in his presentation. Conventional CWDM4 dispersion levels, taking into account conventional tolerance of +/- 6.5 nm: 1271 nm channel: -5.87 ps/nm.km 1331 nm channel: +3.3 ps/nm.km Additional CWDM channels: 1351 nm channel: +4.96 ps/nm.km 1371 nm channel: +6.55 ps/nm.km 1391 nm channel: +8.07 ps/nm.km 1411 nm channel: +9.54 ps/nm.km As one can see, from 1331 nm to 1411 nm the chromatic dispersion coefficient increases from 3.3 ps/nm.km to 9.54 ps/nm.km which is almost x3, which is quite significant. The test results from the 802.3cu TF were contained in
https://www.ieee802.org/3/cu/public/Sept19/stassar_3cu_01_0919.pdf. As I clarified, I believe the group would be interested to see test data how tripling the amount of dispersion in a CWDM8 configuration could be established without a strong increase of dispersion penalty (TDECQ minus TECQ). Kind regards, Peter Stassar (Huawei) To unsubscribe from the STDS-802-3-B400G list, click the following link: https://listserv.ieee.org/cgi-bin/wa?SUBED1=STDS-802-3-B400G&A=1 |