[STDS-802-16] Fwd: Re: 802.16 comment
>I am reading 802.16-2004, section 8.3.1.1.1, page 427. The text below
>figure 195 reads:
>"The transmitter energy increases with the length of the guard time
>while the receiver energy remains the same (the cyclic extension is
>discarded), so there is a 10log(1 - Tg/(Tb + Tg))/log(10) dB loss in
>Eb/No. ..."
>Question:
>Is the base of logarithms 10? If so, since by definition log(10) = 1,
>why is division by log(10) included in the equation? Is there a
>misprint in the text?
>
>Thanks,
>Tim Holmes
>Sr. Principal Engineer
>Dynetics, Inc
>990 Explorer Blvd
>Huntsville, AL, 35806
>256-964-4437
>tim.holmes@dynetics.com